F(x)=4x^2-16x+20

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Solution for F(x)=4x^2-16x+20 equation: 



(F)=4F^2-16F+20

We move all terms to the left:

(F)-(4F^2-16F+20)=0

We get rid of parentheses

-4F^2+F+16F-20=0

We add all the numbers together, and all the variables

-4F^2+17F-20=0

a = -4; b = 17; c = -20;
Δ = b2-4ac
Δ = 172-4·(-4)·(-20)
Δ = -31
Delta is less than zero, so there is no solution for the equation

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